Weekly Integral 7/10/2022
- Ming Zhong
- Jul 17, 2024
- 1 min read
∫(8x^2-4x+7)/((x^2+1)(4x+1))dx
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∫{x}^4dx
∫(x(sin x))/(cos x)^2dx
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∫(8x^2-4x+7)/((x^2+1)(4x+1))dx
∫1/√(√x+2)dx
∫{x}^4dx
∫(x(sin x))/(cos x)^2dx
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