Weekly Integral 4/6/2025
- Ming Zhong
- Apr 6
- 1 min read
∫1/√(√x+2)dx
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∫(x(sin x))/(cos x)^2dx
∫(e^(-x^2024)cos(2024x))/arctan(2024x)dx
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∫1/√(√x+2)dx
∫{x}^4dx
∫(x(sin x))/(cos x)^2dx
∫(e^(-x^2024)cos(2024x))/arctan(2024x)dx
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