Weekly Integral 3/16/2025
- Ming Zhong
- Mar 16
- 1 min read
∫(e^(-x^2024)cos(2024x))/arctan(2024x)dx
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See All∫1/√(√x+2)dx
∫{x}^4dx
∫(x(sin x))/(cos x)^2dx
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∫(e^(-x^2024)cos(2024x))/arctan(2024x)dx
∫1/√(√x+2)dx
∫{x}^4dx
∫(x(sin x))/(cos x)^2dx
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