Weekly Integral 12/11/2022
- Ming Zhong
- Jul 18, 2024
- 1 min read
∫(2x^3+3x^2+4)/(x+1)^4dx
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See All∫1/√(√x+2)dx
∫{x}^4dx
∫(x(sin x))/(cos x)^2dx
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∫(2x^3+3x^2+4)/(x+1)^4dx
∫1/√(√x+2)dx
∫{x}^4dx
∫(x(sin x))/(cos x)^2dx
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